An example of (d) is the following: the values of quantities expressed in ångströms, such as the wavelengths of visible laser radiations, are usually converted to values expressed in nanometers, not meters. More generally, if desired, one can eliminate powers of 10 that appear in converted values as a result of using the conversion factors (or simply factors for brevity) of Sec. B.8 and Sec. B.9 by selecting an appropriate SI prefix (see Sec. B.3).
Examples: 3.523 907 E-02 means 3.523 907 × 10-2 = 0.035 239 07 3.386 389 E+03 means 3.386 389 × 103 = 3386.389
A factor in boldface is exact. All other factors have been rounded to the significant digits given in accordance with accepted practice (see Sec. 7.9, Sec. B.7.2, and Refs. [6: ISO 31-0] and [8]). Where less than six digits after the decimal place are given, the unit does not warrant a greater number of digits in its conversion. However, for the convenience of the user, this practice is not followed for all such units, including the cord, cup, quad, and teaspoon.
| To convert from | to | Multiply by |
|---|---|---|
| atmosphere, standard (atm) | pascal (Pa) | 1.013 25 E+05 |
| cubic foot per second (ft3/s) | cubic meter per second (m3/s) | 2.831 685 E-02 |
| means | 1 atm = 101 325 Pa (exactly) |
| 1 ft3/s = 0.028 316 85 m3/s |
Thus to express, for example, the pressure p = 11.8 standard atmospheres (atm) in pascals (Pa), write
p = 11.8 atm × 101 325 Pa/atmand obtain the converted numerical value 11.8 × 101 325 = 1 195 635 and the converted value p = 1.20 MPa.
Notes:
The factors for derived units not included in Sec. B.8 and Sec. B.9 can readily be found from the factors given.
| Examples: | To find the factor for converting values in lb · ft/s to
values in kg · m/s, obtain from
Sec. B.8 or
Sec. B.9 |
|
1 lb = 4.535 924 E-01 kg 1 ft = 3.048 E-01 m |
and substitute these values into the unit lb · ft/s to obtain
and the factor is 1.382 550 E-01.
1 lb · ft/s = 0.453 592 4 kg × 0.3048 m/s = 0.138 255 0 kg · m/s
To find the factor for converting values in (avoirdupois) oz · in2 to values in kg · m2, obtain from Sec. B.8 or Sec. B.9
1 oz = 2.834 952 E-02 kgand substitute these values into the unit oz · in2 to obtain
1 in2 = 6.4516 E-04 m2
and the factor is 1.828 998 E-05.
1 oz · in2 = 0.028 349 52 kg × 0.000 645 16 m2 = 0.000 018 289 98 kg · m2
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ACCELERATION ANGLE AREA AND SECOND MOMENT OF AREA CAPACITY (see VOLUME) DENSITY (that is, MASS DENSITY - see MASS DIVIDED BY VOLUME) ELECTRICITY and MAGNETISM ENERGY (includes WORK) ENERGY DIVIDED BY AREA TIME FLOW (see MASS DIVIDED BY TIME or VOLUME DIVIDED BY TIME) FORCE FORCE DIVIDED BY AREA (see PRESSURE) FORCE DIVIDED BY LENGTH HEAT Available Energy Coefficient of Heat Transfer Density of Heat Density of Heat Flow Rate Fuel Consumption Heat Capacity and Entropy Heat Flow Rate Specific Heat Capacity and Specific Entropy Thermal Conductivity Thermal Diffusivity Thermal Insulance Thermal Resistance Thermal Resistivity |
LENGTH LIGHT MASS and MOMENT OF INERTIA MASS DENSITY (see MASS DIVIDED BY VOLUME) MASS DIVIDED BY AREA MASS DIVIDED BY CAPACITY (see MASS DIVIDED BY VOLUME) MASS DIVIDED BY LENGTH MASS DIVIDED BY TIME (includes FLOW) MASS DIVIDED BY VOLUME (includes MASS DENSITY and MASS CONCENTRATION) MOMENT OF FORCE or TORQUE MOMENT OF FORCE or TORQUE, DIVIDED BY LENGTH PERMEABILITY POWER PRESSURE or STRESS (FORCE DIVIDED BY AREA) RADIOLOGY SPEED (see VELOCITY) STRESS (see PRESSURE) TEMPERATURE TEMPERATURE INTERVAL TIME TORQUE (see MOMENT OF FORCE) VELOCITY (includes SPEED) VISCOSITY, DYNAMIC VISCOSITY, KINEMATIC VOLUME (includes CAPACITY) VOLUME DIVIDED BY TIME (includes FLOW) WORK (see ENERGY) |
In Sec. B.8 and B.9, the units in the left-hand columns are written as they are often used customarily; the rules and style conventions recommended in this Guide are not necessarily observed. Further, many are obsolete and some are not consistent with good technical practice. The corresponding units in the center columns are, however, written in accordance with the rules and style conventions recommended in this Guide.
In 1959 the definition of the yard was changed to bring the U.S. yard and the yard used in other countries into agreement. Since then the yard has been defined as exactly equal to 0.9144 m, and thus the foot has been defined as exactly equal to 0.3048 m. At the same time it was decided that any data expressed in feet derived from geodetic surveys within the United States would continue to bear the relationship as defined in 1893, namely, 1 ft = (1200/3937) m (ft is the unit symbol for the foot). The name of this foot is "U.S. survey foot," while the name of the new foot defined in 1959 is "international foot." The two are related to each other through the expression 1 international foot = 0.999 998 U.S. survey foot exactly.
In Sec. B.8 and Sec. B.9, the factors given are based on the international foot unless otherwise indicated. Users of this Guide may also find the following summary of exact relationships helpful, where for convenience the symbols ft and mi, that is, ft and mi in italic type, indicate that it is the U.S. survey foot or U.S. survey mile that is meant rather than the international foot (ft) or international mile (mi), and where rd is the unit symbol for the rod and fur is the unit symbol for the furlong.
1 ft = (1200/3937) m
1 ft = 0.3048 m
1 ft = 0.999 998 ft
1 rd, pole, or perch = 16½ ft
40 rd = 1 fur = 660 ft
8 fur = 1 U.S. survey mile (also called "statute mile") = 1 mi = 5280 ft
1 fathom = 6 ft
1 international mile = 1 mi = 5280 ft
272¼ ft2 = 1 rd2
160 rd2 = 1 acre = 43 560ft2
640 acre = 1 mi2
Example: 6.974 951 5 rounded to 3 digits is 6.97
Examples: 6.974 951 5 rounded to 2 digits is 7.0 6.974 951 5 rounded to 5 digits is 6.9750
Examples: 6.974 951 5 rounded to 7 digits is 6.974 952 6.974 950 5 rounded to 7 digits is 6.974 950.
The use of the factors given in Sec. B.8 and Sec. B.9 to convert values of quantities was demonstrated in Sec. B.3. In most cases the product of the unconverted numerical value and the factor will be a numerical value with a number of digits that exceeds the number of significant digits (see Sec. 7.9) of the unconverted numerical value. Proper conversion procedure requires rounding this converted numerical value to the number of significant digits that is consistent with the maximum possible rounding error of the unconverted numerical value.
Example: To express the value l = 36 ftin meters, use the factor 3.048 E-01 from Sec. B.8 or Sec. B.9 and write
The final result, l = 11.0 m, is based on the following reasoning: The numerical value "36" has two significant digits, and thus a relative maximum possible rounding error (abbreviated RE in this Guide for simplicity) of ± 0.5/36 = ± 1.4 % because it could have resulted from rounding the number 35.5, 36.5, or any number between 35.5 and 36.5. To be consistent with this RE, the converted numerical value "10.9728" is rounded to 11.0 or three significant digits because the number 11.0 has an RE of ± 0.05/11.0 = ± 0.45 %. Although this ± 0.45 % RE is one-third of the ± 1.4 % RE of the unconverted numerical value "36," if the converted numerical value "10.9728" had been rounded to 11 or two significant digits, information contained in the unconverted numerical value "36" would have been lost. This is because the RE of the numerical value "11" is ± 0.5/11 = ± 4.5 %, which is three times the ± 1.4 % RE of the unconverted numerical value "36." This example therefore shows that when selecting the number of digits to retain in the numerical value of a converted quantity, one must often choose between discarding information or providing unwarranted information. Consideration of the end use of the converted value can often help one decide which choice to make.
Note: Consider that one had been told initially that the value l = 36 ft had been rounded to the nearest inch. Then in this case, since l is known to within ± 1 in, the RE of the numerical value "36" is ± 1 in/(36 ft × 12 in/ft) = ± 0.23 %. Although this is less than the ± 0.45 % RE of the number 11.0, it is comparable to it. Therefore, the result l = 11.0 m is still given as the converted value. (Note that the numerical value "10.97" would give excessive unwarranted information because it has an RE that is one-fifth of ± 0.23 %.)
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